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Haha! Nice those sparks!

This is a nice overview.

I think there's a 10 running around loose. I may have missed something but I'm getting 3.9 x 10^4 [N]

Really interesting problem.

😎 👍

can you help me out with making out the animation to understand the stability of the system for different parameter values in the mathieu equation?

Nice and clear!

How do we get the law V=k.. Q/r from this law V=k.E/Q

Amazing!

Super applications. :)

How does the problem change when you have a pendulum in 3D space? when I plug my z value in, is it also lcos(theta)(theta-dot)? Or would the angle be different when referring to z? And then how does that affect the rest of the process??

The x-component of Vb2 = (5.5x9 - 0.85x15xcos85)/5.5 = 8.80 m/s, not 1.43 m/s. The ball's speed after the collision is 9.1 m/s, a slight increase. Since pin's direction is almost perpendicular to the x-axis, this is an almost "missed shot". Thus we expect the ball's speed to barely change.

He doesn’t know that CLx on the 15C clears the X register? Next, his calculators are so banged up? As he says he’s not a calculator guy. What’s he doing with them when he can’t even take good care of them? For starters, look at what his 28S looks like.

would you normally include the spin of the ball before and after in your total momentum equation?

😎

How to calculate the velocity of the ball exactly when its leaving the spring without dealing with Energy?

Amazing stuff!

You could have made this video an hour long and it would have been super interesting.

Don't you need to use the magnitude of Vb2 when you're doing the kinetic energy? I get Vb2 = 3.35 [m/s]

Sir, i am afraid you are simplying a bit. You have external forces from the lane. Can you please do the whole problem from release to impact with respect to angular momentum, cg displacement and rg values?

😎 I get Fp = 1.89 N, that's with python and a calculator.

Love your work! Please make video playlists on theoretical classical mechanics, statistical mechanics, and quantum mechanics as well, if possible. 🌹

Sir can you please make a video on how to use physics tools in cheggs

Love this guy ❤

Love the orbital tutorials you've done! Dunno if you're interested, but a slightly-in-depth look at the working of the rotational matrix that can turn a simple "2D" elliptical orbit points into one correctly rotated in 3D space to correct for inclination, argument of periapsis and longitude of ascending node. Kinda crazy to me you can put a bunch of sins and coses and 0s/1s and bam, its got all the correct rotations it should have.

❤❤❤❤❤. Thanks a lot.

Good presentation, but there are some errors. Probabilities of a wave function (in both cases, superposition case and single eigenfunction/eigenvalue case) were not written properly on the sheets. Where are the integrals? The product of psi*psi must be integrated for a continuous basis in order to obtain physically meaninful probabilities... that's why x=x+delta_x is being used in Python script...

T was chosen by the person who introduced the concept of kinetic energy. It stands for "translational" cause it's the energy of movement

Lightbulb isn't great as a constant resistance with current, right?

Embarrassedly Confusing!

We live in a 3d world with a time dimension, so 4d. Let's downgrade that for a minute. We do two dimensions with a time dimension, but we use 3d. Because I suck at math. Let's go with the polynomial that we use to define arcsin, but change it up a bit. x^2-i*2*x*sin(θ)-1 r[1]=cos(θ) +i*sin(θ) r[2]=-cos(θ) +i*sin(θ) f := t -> (r[1]^t - r[2]^t)/(r[1] - r[2]) f(t) = (e^(i*t*θ)-e^(i*t*(π-θ)))/(e^(i*θ)-e^(i*(π-θ))) = (e^(i*t*ln(r_1))-e^(i*t*ln(r_2))/(e^(i*ln(r_1)-e^(i*ln(r_2)) int_0^n f(t) dt = -(r[2]^n*ln(r[1]) - r[1]^n*ln(r[2]) - ln(r[1]) + ln(r[2]))/((r[1] - r[2])*ln(r[1])*ln(r[2])) As you've clearly demonstrated in this video, we divide time up into the cycles that we observe. If we did θ=π/5, it would be a perfect cycle, but our cycles are not perfect. It might be θ=arcsin(3/5). If we observe time by distance traveled, we need to measure arclength from the origin. [t, Re(f(t)), Im(f(t))] x(t)=1, derivative of t is 1. y(t)=Re(d/(dt) (f(t))=Re(-(r[2]^n*ln(r[1]) - r[1]^n*ln(r[2]) - ln(r[1]) + ln(r[2]))/((r[1] - r[2])*ln(r[1])*ln(r[2]))) z(t)=Im(d/(dt) (f(t))=Im(-(r[2]^n*ln(r[1]) - r[1]^n*ln(r[2]) - ln(r[1]) + ln(r[2]))/((r[1] - r[2])*ln(r[1])*ln(r[2]))) int_0^n sqrt(x(t)+y(t)^2+z(t)^2) dt I think this is generalized to all quadratics, but I could be wrong. I don't know enough about either of these subjects to make such a claim. But you get what I mean thought, right? Sorry if my notation is bad. Or I did something wrong, and it confused you.

❤❤❤❤❤.

2sin(x)cos(x) = sin(2x)

Interesting problem! 😎

19:51 what?

You should do the one with 2 balls, one top of another and they're dropped and the top ball is cast high into the air.

That leftover 'r' was gonna be trouble!

Real nice! 🌍

Interesting problem.

Really enjoyed it, thanks a lot Dr. Allain.

Thanks man ❤

The placement of the ad is epic.

❤❤❤❤❤.

Magnit videos

but there is a problem. The area here is not a conserved area. So it would be a mistake to use ohm's law

I enjoyed your response when the graph appears!

Speechless.

Thank you! I was trying to get this result myself and every other example of finding a sphere’s I started with the assumption of the I of a small disk, which seemed unfair. This seems much more generalized.

Pretty sure the "figure 8" question was a trick question to see if you realize the emf would cancel...as you opined.

The diameter is 2.2 cm, so the radius = 1.1 cm , or 0.011 m. So the emf I get is: Emf = 0.276 V